192.168.1.0/29
11111111.11111111.11111111.11111000
255.255.255.248
1. Jumlah subnet = 2^x
= 2^5
= 32
2. Jumlah host = 2^y -2
= 2^3-2
= 6
3. Blok subnet = 256-248
= 8
berarti total ada 32 blok subnet dimulai dari 0,8,16,24,32,40,48,56,64,72, 80,88,96,104,112,120,128,136,144,152,160,168,176,184,192,200,208,216,224,232,240,248
karena absen saya 11 maka saya menggunakan angka ke 11 yaitu 80
jadi...
subnet = 192.168.1.80
host pertama = 192.168.1.81
host terakhir = 192.168.1.86
broadcast = 192.168.1.87
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